here one more array in the pipe prisoner..

Hello,

From a source of mine:

local / typeset = variables declared with local are in scope for the
current shell. The typeset built-in command can also be used to declare
variables.

export = global variables, called also environment variables, are
set for the currently running shell and any process spawned from that
shell.


By *the local boat* should be:

local mypath="/home"
local myfile="file.txt"
local line=""
local arg
local y=0

y=0
arg[$y]="hello"
y=$y+1
arg[$y]="dan"
y=$y+1
arg[$y]="nuggetsman"

#debug
echo ${arg[0]}
echo ${arg[1]}
echo ${arg[2]}

y=0

cat $mypath'/'$myfile |
while read -r line
do

#debug
echo "y="$y
echo "line="$line

arg[$y]=$line

#debug
echo "arg[y]="${arg[$y]}

y=$y+1
done

#debug
echo ${arg[0]}
echo ${arg[1]}
echo ${arg[2]}

exit 1


By *the export boat* should be:

local mypath="/home"
local myfile="file.txt"

export arg1="hello"
export arg2="dan"
export arg3="nuggetsman"
export line=""
export y=0

#debug
echo $arg1
echo $arg2
echo $arg3

y=0

cat $mypath'/'$myfile |
while read -r line
do
#debug
echo "y="$y
echo "line="$line

case $y in
0 )
export arg1=$line

#debug
echo "arg1="$arg1
;;
1 )
export arg2=$line

#debug
echo "arg2="$arg2
;;
2 )
export arg3=$line

#debug
echo "arg3="$arg3
;;
esac

y=$y+1
done

#debug
echo $arg1
echo $arg2
echo $arg3

exit 1


The final result is always:

hello
dan
nuggetsman


Can't solve the quiz, any hint?



Dan

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